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Balance the following skeleton ionic reaction, and calculate E°cell to decide whether the reaction is spontaneous: Ag(s) + Cu2+ (aq) LaTeX: \longrightarrow⟶ Ag+ (aq) + Cu(s) Enter a number so 1, 2, 3 etc E°cell = spontaneous? enter yes or no (MTS 3/3/2019)

Answer :

pstnonsonjoku

Answer:

2Ag(s) + Cu^2+(aq) ----------> 2Ag^+(aq) + Cu(s)

Explanation:

Ag(s)/Ag^+ (aq) is the anode as shown while Cu^2+(aq)/Cu^2(s) is the cathode.

E°cell= E°cathode -E°anode= 0.34 -0.80= -0.5V

The cell is not spontaneous as written because E°cell is negative. This implies that the electrodes of the cell must be interchanged to make the cell spontaneous.

okpalawalter8

The balanced equation and the Ecell is mathematically given as

2Ag(s) + Cu2+ (aq) ⟶ 2Ag+ (aq) + Cu(s)

Ecell = +1.14 V.

What is E°cell to decide whether the reaction is spontaneous?

Question Parameter(s):

Ag(s) + Cu2+ (aq) ------> Ag+ (aq) + Cu(s

Generally, the equation for the Chemical Reaction  is mathematically given as

Ag(s) + Cu2+ (aq) ------> Ag+ (aq) + Cu(s)

Therefore,the Reduction reaction and Oxidation reaction are

Reduction reaction

Cu2+(aq) + 2e ----->> Cu(s)

E = 0.34 V

Oxidation reaction

2Ag(s) --> 2Ag+(aq) + 2e-

E = -0.80 V

In conclusion

2Ag(s) + Cu2+ (aq) ⟶ 2Ag+ (aq) + Cu(s)

Ecell = Ecath - Eano

Ecell = 0.34 - (-0.80)

Ecell = +1.14 V.

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