Step-by-step explanation:
[tex]3 {x}^{2} - 5x + 1 = 0[/tex]
[tex]x = \frac{-b± \sqrt{ {b }^{2} - 4ac } }{2a} [/tex]
here,a= 3 b= -5 and c= 1
[tex]x = \frac{-( - 5)± \sqrt{ {(-5)}^{2} - 4.3.1 } }{2.3} [/tex]
[tex]x = \frac{5 + \sqrt{13} }{6} or \frac{5 - \sqrt{13} }{6} [/tex]
option B and D
