Answer :
Answer:
0.30M
Explanation:
Let solution 1 be the concentrated solution and solution 2 be the diluted solution
(Molarity x Volume)₁ = (Molarity x Volume)₂
(122ml)₁·(1.2M)₁ = (M)₂·(500ml)₂ => M₂ = 122ml ·1.2M / 500ml = 0.2928M ≅ 0.30M
The molarity of the diluted solution is 0.29 M
From the question,
We are to determine the molarity of the diluted solution.
Using the dilution law formula
M₁V₁ = M₂V₂
Where
M₁ is the initial molarity
V₁ is the initial volume
M₂ is the final molarity
and V₂ is the final volume
From the given information,
M₁ = 1.2 M
V₁ = 122 mL
V₂ = 500.0 mL
Putting the parameters into the formula, we get
[tex]1.2 \times 122 = M_{2} \times 500.0[/tex]
∴ [tex]M_{2} = \frac{1.2 \times 122}{500.0}[/tex]
[tex]M_{2} = \frac{146.4}{500.0}[/tex]
∴ M₂ = 0.2928 M
M₂ ≅ 0.29 M
Hence, the molarity of the diluted solution is 0.29 M
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