Answer :
Answer:
Change that occurred to the system reliability = 0.016
Explanation:
Overall system reliability consisting of 4 components J/K/L/M is
= Reliability of J x Reliability of K x Reliability of L x Reliability of M
= 0.99 X 0.98 X 0.992 X 0.998
= 0.960
Let the subsystem consisting f K along with its back up is Called K1
Thus ,
Reliability of K1 = 1- ( 1 – Reliability of K) x ( 1 – Reliability of Backup )
= 1 – ( 1 – 0.98) x ( 1 – 0.80)
= 1 – 0.02 x 0.2
= 1 – 0.004
= 0.996
Thus revised System reliability
= Reliability of J x Reliability of K1 x Reliability of L x Reliability M
= 0.99 X 0.996 X 0.992 X 0.998
= 0.976
Thus, Revised system reliability = 0.976
Thus change in system reliability
= Revised System reliability – Initial system reliability
= 0.976 – 0.960
= 0.016
The change that occurred to the system reliability is 0.016
- The calculation is as follows:
Overall system reliability consisting of 4 components J/K/L/M is
= Reliability of J × Reliability of K × Reliability of L × Reliability of M
= 0.99 × 0.98 × 0.992 × 0.998
= 0.960
Let the subsystem consisting f K along with its back up is Called K1
Thus ,
Reliability of K1 = 1- ( 1 – Reliability of K) × ( 1 – Reliability of Backup )
= 1 – ( 1 – 0.98) × ( 1 – 0.80)
= 1 – 0.02 × 0.2
= 1 – 0.004
= 0.996
Thus revised System reliability
= Reliability of J × Reliability of K1 × Reliability of L × Reliability M
= 0.99 × 0.996 × 0.992 × 0.998
= 0.976
Thus, Revised system reliability = 0.976
Thus change in system reliability
= Revised System reliability – Initial system reliability
= 0.976 – 0.960
= 0.016
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