Answer :
Answer:
The work done by the drag force is given by 29.96 J
Explanation:
Given :
Thrust force [tex]F = 12.3[/tex] N
Displacement [tex]d = 10.2[/tex] m
Mass of rocket [tex]m = 0.663[/tex] Kg
From work energy theorem,
[tex]W = \Delta K[/tex]
[tex]W_{t} - Wd - W_{g} = KE[/tex]
Where [tex]W_{t} =[/tex] thrust work [tex]W_{g} =[/tex] gravitational work
[tex]KE = 12.3 \times 10.2 -Wd - 0.663 \times 9.8 \times 10.2[/tex]
[tex]KE = 59.2 -Wd[/tex]
After cutoff kinetic energy is converted into potential energy,
[tex]KE = Wd' + mg\Delta h[/tex]
Put value of KE
[tex]59.2 -Wd = Wd' + 0.663 \times 9.8 \times 4.5[/tex]
Work done by drag force is given by,
[tex]Wd'+Wd = 59.2 -29.23[/tex]
[tex]= 29.96[/tex] J
Therefore, the work done by the drag force is given by 29.96 J