Answer :
Answer:
271.23 kN
Explanation:
Given that:
The depth of the hole(h) = 2.40 m
The width of the concrete foundation = 9.60 m
Area of the foundation (A) = 2.40 * 9.60 m² = 23.04 m²
The force the water causes on the foundation wall now is calculated using the formula:
[tex]F = \frac{1}{2} h \rho_{\omega}g*A[/tex]
= [tex]\frac{1}{2}*2.40*100*9.81*23.04[/tex]
= 271.23 kN