Answer:
Answer is given below with explanations.
Step-by-step explanation:
[tex]given \: ab \: is \: parallel \: to \: dc \\ by \:corollary \: of thales \: theorem \\ \frac{ab }{dc} = \frac{be}{dc} = \frac{ae}{de} \\ hence \: triangle \: abe \: is \: similar \: to \: triangle \: dce[/tex]
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