Answer :
Answer:
The induced loop in coil is 0.0171 V and induced current in the loop is 0.0284 A
Explanation:
Given:
Area of loop [tex]A = 0.090[/tex] [tex]m^{2}[/tex]
Initial magnetic field [tex]B = 3.80[/tex] T
Rate of magnetic field [tex]\frac{dB}{dt} = 0.190[/tex] [tex]\frac{T}{s}[/tex]
(a)
From the formula of faraday's law,
Induced emf is given by,
[tex]\epsilon =- \frac{d\phi}{dt}[/tex]
Where [tex]\phi =[/tex] magnetic flux
[tex]\phi = BA[/tex]
Put the value of [tex]\phi[/tex] in above equation,
[tex]\epsilon = A\frac{dB}{dt}[/tex]
[tex]\epsilon = 0.090 \times 0.190[/tex]
[tex]\epsilon = 0.0171[/tex] V
(b)
Resistance [tex]R =[/tex] 0.600Ω
The induced current in the loop is given by,
[tex]\epsilon = IR[/tex]
[tex]I = \frac{\epsilon}{R}[/tex]
[tex]I = \frac{0.0171}{0.600}[/tex]
[tex]I = 0.0284[/tex] A
Therefore, the induced loop in coil is 0.0171 V and induced current in the loop is 0.0284 A