Answer:
0.89 moles of N2 gas
Explanation:
From Avogadro's law:
V1/n1 = V2/n2
n2 = V2n1/V1
V1=11.2L
V2= 20L
n1=0.5 moles
n2 = ??
Therefore
n2= 20×0.5/11.2= 0.89 moles
Answer:
0.8929 mol
Explanation:
An 11.2-L sample of gas is determined to contain .50 mol N2. at the same temperature and pressure, how many moles of gas would there be in a 20. -L sample?
According to avogadro's law
[tex]\frac{V_1}{n_1} = \frac{V_2}{n_2}[/tex]
From the given data
V1 = 11.2L
n1 = 0.5mole
V2 = 20L
n2 =?
[tex]\frac{11.2}{0.5} = \frac{20}{?}[/tex]
[tex]22.4=\frac{20}{?} \\\\= \frac{20}{24} \\\\= 0.8929[/tex]
= 0.8929 mol
