Answer :
Answer:
[tex]\frac{8}{441}[/tex]
Step-by-step explanation:
Blue Skirt = 3
White Skirt = 1
Khaki Pant = 2
Jeans = 4
Short Sleeve = 3
Long Sleeve = 5
Sweatshirt = 2
Sweater = 1
We want probability of jeans and a sweatshirt.
In probability, "AND" means "Multiplication" and "OR" means "Addition"
We want probability of jeans and probability of sweatshirt, and then "ADD THEM UP"
Total amount = 3 + 1 + 2 + 4 + 3 + 5 + 2 + 1 = 21
Probability (jeans) = 4/21
Probability (sweatshirt) = 2/21
Probability (Jeans & Sweatshirt) = (4/21) * (2*21) = 8/441
The probability is [tex]\frac{8}{441}[/tex]
Answer:
Step-by-step explanation:
So we could have the following 6 combinations with Shirt A:
Shirt A, Skirt A, Shoe A
Shirt A, Skirt A, Shoe B
Shirt A, Skirt B, Shoe A
Shirt A, Skirt B, Shoe B
Shirt A, Skirt C, Shoe A
Shirt A, Skirt C, Shoe B
Consider that there are four other shirts that will also have 6 combinations of skirts and shirts that will go with them. Now, there are 5×6 total combinations which is 30 ways that Sofia could dress the mannequin.
Ralph is trying to purchase a new car. The salesperson tells him that there are 8 different possible interior colors, 5 exterior colors and 3 car models to choose from. How many different unique cars does he have to choose from?
Instead of making a tree diagram this time, let’s look at a more efficient method for determining the number of combinations. If we consider what happens in the tree diagram, the 8 different interior colors would each be matched with each of the 5 exterior colors and those combinations would then be linked to the 3 different models, we can see that:
8 interior colors×5 exterior colors× 3 models=8×5×3=120 combinations
Monique is having a 5 course dinner in the dining room on a cruise. The menu consists of 2 appetizers, 3 soups, 2 salads, 4 entrees and 3 desserts. How many different meals could be configured if she chooses one of each course?
Following the method described in #2 above, we can multiply the number of choices for each course together to determine the total combinations:
2×3×2×4×3=144 unique 5 course meals tell me if im right