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Two particles carrying charges q1 and q2 are separated by a distance r and exert an electric force F⃗ E on each other. If q1 is doubled, what change must you make to one of the other variables in order to keep the magnitude FE constant? There is more than one answer.

Answer :

pstnonsonjoku

Answer:

q2 must also be doubled

r may also be halved

Explanation:

According to Coulumbs law

F= K q1 q2/r^2

If q1 is doubled, we must necessarily double q2 and r may also be halved in order to maintain F at the same value. Once the value of F is thus kept constant and E is also constant, the product FE must remain constant.

onyebuchinnaji

In order to keep the magnitude electric force constant, when the first charge is doubled, the second charge should be halved.

The given parameters:

  • Charge of first particle, = q1
  • Charge of second particle, = q2
  • Distance between the two particles, = r
  • Electric force = F

The electrostatic force between the two charges is calculated as follows;

[tex]F = \frac{kq_1q_2}{r^2}[/tex]

When the first charge is doubled, the second charge should be halved as well.

[tex]F = \frac{k (2q_1) (0.5q_2)}{r^2} \\\\F = \frac{k(2q_1)(q_2)}{2r^2}[/tex]

Thus, In order to keep the magnitude electric force constant, when the first charge is doubled, the second charge should be halved.

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