Answer:
Force on each conductors = 4x10^-3 N
The force between the wires are attractive so the direction of this force is towards each other
Answer:
The magnitude and direction of the force is 0.09 N, attractive
Explanation:
The magnitude of the force is:
[tex]F=\frac{u_{o}I_{1}I_{2}L_{2} }{2\pi d}[/tex]
Where
d = distance = 4 cm = 0.04 m
uo = constant = 4πx10⁻⁷Tm/A
I₁ = 30 A
I₂ = 30 A
L = 20 m
Replacing:
[tex]F=\frac{4\pi x10^{-7}*30*30*20 }{2\pi *0.04} =0.09N[/tex] attractive
