Answer :
Explanation:
Given that,
Mass of bus, m = 6110 kg
Speed of bus, v = 20 m/s
The bus will stop in 24 s gently applying the brakes, t = 24 s
The average force exerted on the bus is given by :
[tex]Ft=mv\\\\F=\dfrac{mv}{t}\\\\F=\dfrac{6110\times 20}{24}=5091.67\ N[/tex]
If the driver slams on the brakes, the stops in 3.90 s, t' = 3.9 s
The average force exerted on the bus at this time is given by :
[tex]F't=mv\\\\F'=\dfrac{mv}{t'}\\\\F'=\dfrac{6110\times 20}{3.9}=31333.34\ N[/tex]
Hence, this is the required solution.