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Children inherit their blood type from their parents, with probabilities that reflect the parents' genetic makeup. Children of Juan and Maria each have probability 1/4 of having blood type A and inherit independently of each other. Juan and Maria plan to have 4 children; let X be the number who have blood type A. (a) What are n and p in the binomial distribution of X

Answer :

Answer:

[tex]n = 4, p = 0.25[/tex]

Step-by-step explanation:

We are given the following in the question:

We treat adult having blood type A as a success.

P(Blood type A) =

[tex]p=\dfrac{1}{4} = 0.25[/tex]

Then the number of Children of Juan and Maria who have blood type A follows a binomial distribution as there are

  • n independent trial.
  • Each trial have to outcomes(Blood type A or not)
  • Probability of success is same for each success

Here,

[tex]P(X=x) = \binom{n}{x}.p^x.(1-p)^{n-x}[/tex]

where n is the total number of observations, x is the number of success, p is the probability of success.

Thus, for the given binomial distribution,

[tex]n = 4, p = 0.25[/tex]

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