Answer :
Answer:
The moles of starting material is [tex]1.8212 \times 10^{-2}[/tex] mole
Explanation:
Given:
Cyclohexene oxide material is used
Density = 0.97[tex]\frac{g}{mL}[/tex]
Volume = 1.84 mL
Formula of Cyclohexene oxide = [tex]C_{6} H_{10} O[/tex]
Molar mass is given by,
[tex]C = 6 \times 12 = 72[/tex]
[tex]H = 10 \times 1 = 10[/tex]
[tex]O = 1 \times 16 = 16[/tex]
⇒ [tex]m' = 96\frac{g}{mol}[/tex]
Mass [tex]m = 0.97 \times 1.84 = 1.7848[/tex] [tex]g[/tex]
Moles is given by,
[tex]n = \frac{m}{m'}[/tex]
[tex]n = \frac{1.7848}{98}[/tex]
[tex]n = 1.8212 \times 10^{-2}[/tex] mol
Therefore, the moles of starting material is [tex]1.8212 \times 10^{-2}[/tex] mole