Answer :
Answer:
The area of he field that is not reached by the sprinkler = 168.56 [tex]m^{2}[/tex]
Step-by-step explanation:
Side of the square field (a) = 28 m
Diameter of circular area (D) = 28 m
Radius of circular area (r)= 14 m
Area made by square field [tex]A_{1} = a^{2}[/tex]
[tex]A_{1} = 28^{2}[/tex] = 784 [tex]m^{2}[/tex]
Area made by circular field [tex]A_{2} = \pi r^{2}[/tex]
[tex]A_{2} = \pi 14^{2}[/tex]
[tex]A_{2}[/tex] = 615.44 [tex]m^{2}[/tex]
Field is not reached by the sprinkler A' = [tex]A_{1} - A_{2}[/tex]
Put the values of [tex]A_{1}[/tex] & [tex]A_{2}[/tex]
A' = 784 - 615.44
A' = 168.56 [tex]m^{2}[/tex]
Therefore the area of he field that is not reached by the sprinkler = 168.56 [tex]m^{2}[/tex]
Answer:
168.56
Step-by-step explanation:
The answer is on the picture below. :)
