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Pat Kinch used a racing cycle to travel 75.57 km/h. Suppose Kinch moved at this speed around a circular track. If the combined mass of Kinch and the cycle was 92.0 kg and the average centripetal force was 12.8 N, what was the radius of the track? What is the unit of the radius?

Answer :

Cricetus

The radius of the track will be "3167 m".

According to the question,

Speed,

  • [tex]v = 75.57 \ km/h[/tex]

or,

         [tex]=75.57\times \frac{1000}{3600}[/tex]

         [tex]= 21 \ m/s[/tex]

Mass,

  • m = 92.0 kg

Force,

  • F = 12.8 N

We know,

→ [tex]F = ma[/tex]

or,

      [tex]= \frac{mv^2}{r}[/tex]

By putting the values,

[tex]12.8=\frac{92\times 21^2}{r}[/tex]

    [tex]r = 3167 \ m[/tex]

Thus the response above is appropriate.  

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