Answer:
the vertex is at (2, 5) and the axis of symmetry is x = 2
Step-by-step explanation:
A word to the wise: Please use " ^ " to indicate exponentiation. And so we have:
y= -2x^2+8x-3
The x-coordinate of the vertex and the equation of the axis of symmetry is determined by the equation
b -8
x = ------- which here is x = ----------- = 2
2a 2(-2)
Then the y-coordinate of the vertex is f(2) = -2(-2)^2 + 8(2) - 3 = 8 - 3 = 5
and so the vertex is at (2, 5) and the axis of symmetry is x = 2
