Answer :
The answer is D. |tan Θ|
√[(1 − cos θ)(1+cos θ)] / cos^2 θ
√(1 - cos^2 θ) / cos^2 θ
|tan Θ|
√[(1 − cos θ)(1+cos θ)] / cos^2 θ
√(1 - cos^2 θ) / cos^2 θ
|tan Θ|
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Answer:
option D is correct.
Step-by-step explanation:
we are given the function [tex]\sqrt{\frac{(1-\cos \theta )(1+\cos \theta )}{\cos ^2\theta }}[/tex]
we know that the expansion is given by [tex](1-\cos \theta )(1+\cos \theta )=1-\cos ^2\theta =\sin ^2\theta[/tex]
so [tex]\sqrt{\frac{(1-\cos \theta )(1+\cos \theta )}{\cos ^2\theta }}=\sqrt{\frac{\sin ^2\theta }{\cos ^2\theta }}=\sqrt{\tan ^2\theta }=|\tan \theta |[/tex]
Hence, option D is correct.