A 1440 kg car has just passed a diner. The closest the car came to the diner was R = 16.5 m , but the car has driven another x = 36.7 m in the 2.05 s elapsed since then. If the car travels at constant speed, what is the current magnitude L of the angular momentum of the car about the diner?

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Today at 12:31 AM
Physics

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A 1440 kg car has just passed a diner. The closest the car came to the diner was R = 16.5 m , but the car has driven another x = 36.7 m in the 2.05 s elapsed since then. If the car travels at constant speed, what is the current magnitude L of the angular momentum of the car about the diner?

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Kazeemsodikisola Kazeemsodikisola · Answer 1 · 2025-03-27T00:36:32-04:00

Kazeemsodikisola Kazeemsodikisola

Today at 12:36 AM

Answer:

Explanation:

Given that,

Mass of car

M = 1440kg

Radius car traveled

R = 16.5m

The car travelled 36.7m in 2.05s

Then, velocity is given as

Velocity = distance / time

V = 36.7/2.05

V = 17.90 m/s

Angular momentum L?

Angular momentum can be calculated using

L = M×R×V

Where

M is mass

R is radius

C is velocity

Then,

L = MRV

L = 1440 × 16.5 × 17.9

L = 425,361.95 kgm²/s

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