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A chemist makes 360mL of calcium sulfate working solution by adding distilled water to 90.0mL of a 10.7mmol/L stock solution of calcium sulfate in water. Calculate the concentration of the chemist's working solution. Round your answer to 3 significant digits.

Answer :

Answer: The concentration of the chemist's working solution is 0.00268 M

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

According to the neutralization law,

[tex]M_1V_1=M_2V_2[/tex]

where,

[tex]M_1[/tex] = molarity of stock solution = 10.7 mmol/L =  0.0107 mol/L  [tex]1mmol=10^{-3}mol[/tex]

[tex]V_1[/tex]  = volume of stock solution = 90.0 ml

[tex]M_2[/tex] = molarity of working  solution = ?

[tex]V_2[/tex] = volume of working solution = 360 ml

[tex]0.0107\times 90.0=M_2\times 360[/tex]

[tex]M_2=0.00268M[/tex]

Thus the concentration of the chemist's working solution is 0.00268 M

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