Answer:
f(16)=162
Step-by-step explanation:
-In a geometric sequence, the quotient between any tow consecutive numbers is called the common ratio,r:
[tex]r=\frac{a_n}{a_{n-1}}[/tex]
Given that f(3)=32 and f(9)=72, we can find the common ratio as below:
[tex]r=\frac{a_n}{a_{n-1}}\\\\\therefore \frac{f(9)}{f(3)}=r^6\\\\\frac{72}{32}=r^6\\\\r^6=2.25\\\\r=2.25^{1/6}[/tex]
#We substitute and use the same formula to find the nth term:
[tex]a_n=ar^{n-1}[/tex]
let f(3) be a(the first term):
[tex]a_n=ar^{n-1}\\\\a_{16}=32(2.25^{1/6})^{16-3-1}\\\\a_{16}=32(2.25^{1/6})^{12}\\\\\\=162[/tex]
Hence, f(16)=162
