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A 2.9 kg ball strikes a wall with a velocity of 8.6 m/s to the left. The ball bounces off with a velocity of 7.3 m/s to the right. If the ball is in contact with the wall for 0.33 s, what is the constant force exerted on the ball by the wall? Answer in units of N.

Answer :

samuelonum1

Answer:

The constant force exerted by the wall is F=11.4N

Explanation:

The problem bothers on the impulse of a force

Which is given as

Ft=mv-mu

Ft=m(v-u)

Given data

mass of ball m =2.9kg

Final speed v=8.6m/s

Initial speed u=7.3m/s

Time t= 0.33s

Substituting to find F

F*0.33=2.9(8.6-7.3)

F*0.33=2.9*1.3

F=3.77/0.33

F=11.4N

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