The following information is given for ether, C2H5OC2H5, at 1atm: boiling point = 34.6 °C Hvap(34.6 °C) = 26.5 kJ/mol specific heat liquid = 2.32 J/g°C /At a pressure of 1 atm, what is H in kJ for the process of condensing a 22.5 g sample of gaseous ether at its normal boiling point of 34.6 °C.

Answer :

Answer:

The heat is  [tex]H= -8.044KJ[/tex]

Explanation:

From the question we are told that

   The pressure is  [tex]P = 1 \ atm[/tex]

    The boiling point is  [tex]B_P = 34^oC[/tex]

     The heat of vaporization at 34°C is  = [tex]26.5 kJ/mol[/tex]

       The specific heat of the liquid is [tex]c_p = 2.32 J/g^oC[/tex]

      The  mass is  [tex]m = 22.5g[/tex]

  The no of moles of the sample of [tex]C_2 H_5OC_2H_5[/tex]  is given as

               [tex]No \ mole (n) = \frac{Mass \ of \ sample }{Molar \ mass }[/tex]

    The  Molar mass for [tex]C_2 H_5OC_2H_5[/tex]  is a value = [tex]= 74.12 g/mol[/tex]

Substituting the value into the above equation

          [tex]n = \frac{22.5}{74.12}[/tex]

                           [tex]= 0.30356 \ mol[/tex]

      The heat H is mathematically as

                [tex]H =- nH_{vap}[/tex]

The negative sign show that the heat is for condensing

            [tex]H = 0.30356 * 26.5 *10^{3} J/mol[/tex]

                [tex]H= -8.044KJ[/tex]

                   

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