Answer :
Answer:
The heat is [tex]H= -8.044KJ[/tex]
Explanation:
From the question we are told that
The pressure is [tex]P = 1 \ atm[/tex]
The boiling point is [tex]B_P = 34^oC[/tex]
The heat of vaporization at 34°C is = [tex]26.5 kJ/mol[/tex]
The specific heat of the liquid is [tex]c_p = 2.32 J/g^oC[/tex]
The mass is [tex]m = 22.5g[/tex]
The no of moles of the sample of [tex]C_2 H_5OC_2H_5[/tex] is given as
[tex]No \ mole (n) = \frac{Mass \ of \ sample }{Molar \ mass }[/tex]
The Molar mass for [tex]C_2 H_5OC_2H_5[/tex] is a value = [tex]= 74.12 g/mol[/tex]
Substituting the value into the above equation
[tex]n = \frac{22.5}{74.12}[/tex]
[tex]= 0.30356 \ mol[/tex]
The heat H is mathematically as
[tex]H =- nH_{vap}[/tex]
The negative sign show that the heat is for condensing
[tex]H = 0.30356 * 26.5 *10^{3} J/mol[/tex]
[tex]H= -8.044KJ[/tex]