Answer :
Answer:
1.04m
Explanation:
the distance is determined by the diameter of the trajectory.
you can find the radius of the trajectory by using the following formula:
[tex]r=\frac{m_cv}{qB}[/tex]
mc : mass of the Big C = 0.303kg/mol/(6.02*10^{23}/mol)=5.03*10^{-25}kg
v: velocity of the ion = 50000m/s
B: magnetic constant = 0.3T
q: 1.6*10^{-19}C
By replacing you obtain:
[tex]r=\frac{(5.03*10^{-25}kg)(50000m/s)}{(1.6*10^{-19}C)(0.3T)}=0.52m[/tex]
the diameter wiil be:
d=2r=1.04m
the ion strikes the detector from 1.04m to the entrance of the spectrometer
The Florida Snow ions strike the spectrometer detector after travelling through a semicircle trajectory will be "1.04 m" far.
Spectrometer
According to the question,
Big C's mass, [tex]m_c[/tex] = [tex]\frac{0.303}{6.02\times 10^{23}}[/tex]
= 5.03 × 10⁻²⁵ kg
Ion's velocity, v = 50000 ms
Magnetic constant, B = 0.3 T
Charge, q = 1.6 × 10⁻¹⁹ C
We know that,
→ r = [tex]\frac{m_c v}{qB}[/tex]
or,
The radius, r = [tex]\frac{5.03\times 10^{-25}\times 50000}{1.6\times 10^{-19}\times 0.3 }[/tex]
= 0.52 m or,
Diameter, d = 2 × r
= 2 × 0.52
= 1.04 m
Thus the above approach is correct.
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