Given:
Given that the radius of the circle is √98 units.
The circle is centered at the point (5.9, 6.7)
We need to determine the equation of the circle.
Equation of the circle:
The general form of the equation of the circle is given by
[tex](x-h)^2+(y-k)^2=r^2[/tex]
where (h,k) is the center and r is the radius of the circle.
Substituting the center point (h,k) = (5.9, 6.7) and r = √98, we get;
[tex](x-5.9)^2+(y-6.7)^2=(\sqrt{98})^2[/tex]
Simplifying, we get;
[tex](x-5.9)^2+(y-6.7)^2=98[/tex]
Thus, the equation of the circle is [tex](x-5.9)^2+(y-6.7)^2=98[/tex]
