Answer :
The heat absorbed by water is 30116 J.
What is heat?
The increment in temperature adds up the thermal energy into the object. This energy is Heat energy.
Given 0.0100 kg ice cube at 0 degree C is melted, warmed to 100 degree C, then boiled off.
The specific heat of water C is 4.186 J/kgK, the latent heat of fusion for ice Li = 33600 J/kg K and latent heat of vaporization Ls = 2,230 J/kg K
The total heat is
Q = m Li + mCΔT + mLs
Substituting the values, we get
Q = 0.01 x 33600 + 0.01 x4.186 x (100 - 0) + 0.01 x 2,230
Q = 30116 J
Thus, the heat absorbed by water is 30116 J.
Learn more about heat.
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