Answer :
Answer:
0.0525 V
Explanation:
Given,
area of the loop, A = 0.250 m²
Magnetic field, B = 0.210 T
θ= 90°
angular speed,ω = 0.530 rad/s
Using emf expression
E = NBAω sin θ
E = 1 x 0.250 x 0.210 x sin 90°
E = 0.0525 V
The emf induced in the loop is equal to 0.0525 V.