Answer :
Answer:
5 a) PMT=$1,465.60
b) Total Payments=$527,616
c) Total Interest=$331,616
6a) Interest=$1,079.93
b) Principal=$584.07
Step-by-step explanation:
a. Given the loan amount is $196,000, annual rate is 8.2% and the loan term is 30 years.
-The monthly mortgage payment can be calculated as follows:
[tex]PMT=A(\frac{(r/n)}{1-(1+\frac{r}{n})^{-nt}})[/tex]
Where:
- PMT is the monthly mortgage payment
- r is the annual interest rate
- n,t is the number of annual payments and time in years respectively
-We substitute to solve for PMT:
[tex]PMT=A(\frac{(r/n)}{1-(1+\frac{r}{n})^{-nt}})\\\\=196000[\frac{(0.082/12)}{1-(1+\frac{0.082}{12})^{-12\times30}}]\\\\=\$1,465.60[/tex]
Hence, the monthly mortgage payment is $1,465.60
b. The total number of payments is obtained by multiplying the total number of payments by the amount of each payment:
[tex]\sum(payments)=PMT\times nt\\\\=1465.60\times 12\times 30\\\\=\$527,616.00[/tex]
Hence, the total amount of payments is $527,616
c. The amount of interest paid over the loan's term is obtained by subtracting the principal loan amount from the total payments made:
[tex]Interest=Payments-Principal\\\\=527,616.00-196,000.00\\\\=\$331,616[/tex]
Hence, an interest amount of $331,616 is paid over the loan's term.
6 a) We first obtain the effective loan amount by subtracting the down-payment:
[tex]Loan \ Amount= Regular \ Price -Downpayment\\\\=205700-0.1(205700)\\\\=\$185,130[/tex]
The interest paid on the first mortgage payment is calculated as below:
[tex]I=\frac{r}{n}\times P\\\\I=Interest\\r=interest \ rate\\n=Payments \ per \ year\\P=Outstanding \ loan \ balance\\\\\therefore I=\frac{0.07}{12}\times 185130\\\\=\$1,079.93[/tex]
Hence, the amount of interest in the first payment is $1,079.93
b. The amount of principal repaid is obtained by subtracting the interest amount from the monthly mortgage payments;
[tex]Principal \ Paid=PMT-Interest\\\\PMT=A[\frac{(r/n)}{1-(1+\frac{r}{n})^{-nt}}]\\\\=185130[\frac{(0.07/12)}{1-(1+\frac{0.07}{12})^{-180}}\\\\=1664.00\\\\\\Principal \ Paid=1664.00-1079.93\\\\=\$584.07[/tex]
Hence, the amount of principal applied is $584.07