Asaltyskid
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A catapult launches a boulder with an upward velocity of 112 ft/s. The height of the boulder, h, in feet after t seconds is given by the function h= -16t^2 + 112t +30 How long does it take the boulder to reach its maximum height? What is the boulder’s maximum height? Round to the nearest hundredth, if necessary.

Answer :

15sunshine
You need to find the vertex of the function. 

The easiest way to do this is to graph it on a calculator like desmos. 

but you can find the line of symmetry with this equation. x=-b/2a

x=-112/2(-16)
x= 3.5

Then plug that into the equation.

-16(3.5)^2+112(3.5)+30

226

226ft is the maximum height.

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