Suppose a single bacterium is placed in a bottle at 11:00am. It grows and at 11:01 divides into two bacteria. These two bacteria each grow and at 11:02 divide into four bacteria. Which grow and at 11:03 divide into eight bacteria, and so on. Now, suppose the bacteria continue to double every minute until the bottle is full at 12:00.


a. How many bacteria are in the bottle at 11:53?


b. What fraction of the bottle is full at that time?

Answer :

Answer:

Number of bacteria at 11:53 for 53 min = [tex]2^{53}[/tex]   = 9.007199 × [tex]10^{15}[/tex]  

fraction that is full = [tex]2^{-7}[/tex]

Step-by-step explanation:

solution

Number of bacteria is express as here

Number of bacteria = [tex]2^t[/tex]    ............1

so

bacteria at 1 min , 2 min and 3 min are

Number of bacteria at 1 min = [tex]2^1[/tex] = 2

Number of bacteria at 3 min = [tex]2^2[/tex] = 4

Number of bacteria at 3 min = [tex]2^3[/tex]  = 8

and

as that Number of bacteria at 11:53 is for 53 min is

Number of bacteria at 11:53 for 53 min = [tex]2^{53}[/tex]   = 9.007199 × [tex]10^{15}[/tex]  

and

bottle is full at 12:00

so Number of bacteria at 12:00 for 60 min = [tex]2^{60}[/tex]  

so fraction that is full = [tex]\frac{2^{53}}{2^{60}}[/tex]

fraction that is full = [tex]2^{-7}[/tex]

A geometric sequence is a sequence of numbers in which the ratio between consecutive terms is constant.

Number of bacteria present in bottle at 11:53  are [tex]2^{53}[/tex].

At that time, fraction [tex]2^{-7}[/tex] or 0.00781 of bottle is full.

Since, single bacterium is placed in a bottle at 11:00am. It grows and at 11:01 divides into two bacteria. These two bacteria each grow and at 11:02 divide into four bacteria. Which grow and at 11:03 divide into eight bacteria.

So, a sequence is obtained  1, 2, 4, 8, 16, 32, 64, .........

We can also write as,

At 11:00 am,    [tex]2^0[/tex] bacteria

At 11:01 am,    [tex]2^1[/tex] bacteria

At 11:02 am,   [tex]2^2[/tex]  bacteria

Similarly,  At 11:53 am, Number of bacteria present in bottle are [tex]2^{53}[/tex].

When the bottle will be full, that time number pf bacteria will be [tex]2^{60}[/tex].

S0, fraction of bottle is full at 11:53 is   [tex]2^{53} /2^{60} = 2^{-7} = 0.00781[/tex]

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