Answer:
The answer to your question is 1544 g of CO₂
Explanation:
Data
mass of octane = 500 g
mass of CO₂ = ?
Balanced chemical reaction
2C₈H₁₈ + 25O₂ ⇒ 16CO₂ + 18H₂O
Process
1.- Calculate the molar mass of octane and of carbon dioxide
C₈H₁₈ = 2[(12 x 8) + (1 x 18)] = 2[(96 + 18] = 2[114] = 228 g
CO₂ = 16[(12 x 1) + (16 x 2)] = 16[12 + 32] = 16[44] = 704 g
2.- Calculate the mass of carbon dioxide produced
228 g of C₈H₁₈ ---------------- 704 g of CO₂
500 g of C₈H₁₈ --------------- x CO₂
x = (500 x 704) / 228
x = 352000/228
x = 1544 g of CO₂
