Answer :
0.2 M is the molarity of a sucrose solution containing 34.2 grams of sucrose in 500.0 ml of water.
Explanation:
Data given:
mass of sucrose = 34.2 grams
volume of water = 500 ml or 0.5 Litres
molar mass of sucrose = 342 grams/mole
molarity = ?
To calculate molarity first we will calculate number of moles provides,
number of moles = [tex]\frac{mass}{ato,ic mass of 1 mole}[/tex]
putting the values in the equation:
number of moles = [tex]\frac{34.2}{342}[/tex]
number of moles = 0.1 mole
now the molarity will be calculated by applying the following formula:
molarity = [tex]\frac{number of moles}{volume in litres}[/tex]
putting the values in the equation:0.2 m
molarity = [tex]\frac{0.1 }{0.5}[/tex]
molarity = 0.2 M
thus the molarity of sucrose solution of 500 ml is 0.2 M
The molarity of a sucrose solution containing 34.2 grams of sucrose in 500.0 mL of water "0.2 M".
Molarity of solution
According to the question,
Molar mass of sucrose = 342.0 g/mole
Volume of water = 500 ml or,
= 0.5 liters
Mass of sucrose = 34.2 grams
Now,
The number of moles will be:
= [tex]\frac{Mass}{Atomic \ mass \ of \ 1 \ mole}[/tex]
By substituting the values,
= [tex]\frac{34.2}{342}[/tex]
= 0.1 mole
hence, The molarity will be:
= [tex]\frac{No. \ of \ moles}{Volume}[/tex]
= [tex]\frac{0.1}{0.5}[/tex]
= 0.2 M
Thus the response above is appropriate.
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