Answer : The new pressure acting on a 2.5 L balloon is, 8.6 atm.
Explanation :
Boyle's Law : It is defined as the pressure of the gas is inversely proportional to the volume of the gas at constant temperature and number of moles.
[tex]P\propto \frac{1}{V}[/tex]
or,
[tex]P_1V_1=P_2V_2[/tex]
where,
[tex]P_1[/tex] = initial pressure = 3.7 atm
[tex]P_2[/tex] = final pressure = ?
[tex]V_1[/tex] = initial volume = 5.8 L
[tex]V_2[/tex] = final volume = 2.5 L
Now put all the given values in the above equation, we get:
[tex]3.7atm\times 5.8L=P_2\times 2.5L[/tex]
[tex]P_2=8.6atm[/tex]
Thus, the new pressure acting on a 2.5 L balloon is, 8.6 atm.