Bucket A contains half as much water as Bucket B. Bucket B contains three times as much water as Bucket C. If Bucket A plus Bucket C holds 1 L 285 ml of water, How much water is in Bucket B?

Answer :

Answer:

Bucket B contains 0.257 L= 257 ml.

Step-by-step explanation:

Given that,

Bucket A contains half as much water as Bucket B.

Bucket B contains three times as much water as Bucket C.

Bucket A and Bucket C holds 1 L 285 ml = 1 L +(285÷10000)L= (1+0.285) L =1.285 L.

Then,

[tex]A\times \frac12=B[/tex]  ⇒ A=2B.....(1)

[tex]3\times B= C[/tex]  ⇒C=3B....(2)

From (1) and (2) we get,

A+C=2B+3B

⇒A+C=5B

⇒1.285 =5B         [ since A+B=1.285 L]

⇒5B=1.285

[tex]\Rightarrow B=\frac{1.285}{5}[/tex]

⇒B = 0.257 L

Bucket B contains 0.257 L= 257 ml

Other Questions