Answer :

lazirlufias

Answer:

[tex]\frac{1}{2y-2y^2}, y\neq 1[/tex]

Step-by-step explanation:

observe by factorization and cancelation

[tex]\frac{y^2+y+1}{-2y(y^3-1)}=\frac{y^2+y+1}{-2y(y-1)(y^2+y+1)}

\\=\frac{1}{-2y(y-1)}

\\=\frac{1}{2y-y^2}[/tex]

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