Answer :
Li ----> Li+ + e-(oxidation)
now comes
Reduction:
H2 + 2e- ------> 2H
now by
Multiplying (1) by 2 and adding in (2) will give you the required equation..
..
2Li + H2 ---------> 2LiH
half reaction are either oxidation or reduction
now comes
Reduction:
H2 + 2e- ------> 2H
now by
Multiplying (1) by 2 and adding in (2) will give you the required equation..
..
2Li + H2 ---------> 2LiH
half reaction are either oxidation or reduction