Answer :
Answer:
Length = 12yards
Width = 14yards
Sum = 26yards
Step-by-step explanation:
Let assume the play ground is rectangular in form.
Area of a rectangle = length × width
Given area of the playground = 168yd²
If the width of the playground is 2yd longer than its length, then:
W = L+2
Substituting W = L+2 into the formula above we have:
A = L × (L+2)
A = L²+2L
168 = L²+2L
L²+2L-168 = 0
L²+14L-12L-168 = 0
L(L+14)-12(L+14) = 0
(L-12)(L+14) = 0
L-12 = 0 and L+14 =0
L = 12 and -14
Taking the positive length, L = 12yards
If Length = 12yards
W = L+2
W = 12+2
Width = 14yards
Sum of the length and width will be:
L+W= 12+14
= 26yards
Answer:
The length of playground is 12 yd
The width of playground is 14 yd
The sum of the length and width of playground is 26 yd
Step-by-step explanation:
The area, A of the playground is given as 168 yd²
The formula for the area of the playground is given as follows;
Area, A of playground = Length, L × Width, W
The Width = length + 2 yd or W = L + 2
Therefore, A = L × (L + 2)
A = L² + 2·L
Where we have A = 168 yd², we have the area equation presented as follows
168 = L² + 2·L or
L² + 2·L - 168 = 0
Factorizing the above equation gives
L = 12 or L = -14 we note that the appropriate solution is L = 12 yd
Therefore W = L + 2 = 12 + 2 = 14 yd
The length of playground = 12 yd
The width of playground = 14 yd
The sum of the length and width of playground = 12 + 14 = 26 yd.