Answer :
[tex]a_1=5;\ a_2=-10;\ r=a_2:a_2\to r=-10:5=-2\\\\a_n=a_1r^{n-1}\\\\\boxed{a_n=5\cdot(-2)^{n-1}}[/tex]
Answer:
- The explicit equation is given by:
[tex]a_n=5(-2)^{n-1}[/tex]
- The domain of the geometric sequence is: All the natural numbers (i.e. n≥1)
Step-by-step explanation:
Explicit formula--
The explicit formula is a formula which is used to represent the nth term of a sequence in terms of the variable n.
It is given that:
The first term of the sequence is 5 and the second term is -10.
This means that if a denotes the first term and r denotes the common ratio.
The geometric sequence is given by: a,ar,ar²,ar³,....
i.e. the nth term of the sequence is given by:
[tex]a_n=ar^{n-1}[/tex]
Then we have:
[tex]a=5[/tex]
and
[tex]ar=-10\\\\i.e.\\\\5\times r=-10\\\\i.e.\\\\r=\dfrac{-10}{5}\\\\i.e.\\\\r=-2[/tex]
Hence, the nth term of the sequence is given by:
[tex]a_n=5(-2)^{n-1}[/tex]
We know that the domain of a geometric sequence is the set of all the natural numbers.
( since the term a_n is defined for all the natural numbers ).