Answer :

Panoyin
[tex]a_{n} = 6\frac{2}{3} + \frac{1}{3}(n - 1)[/tex]
[tex]a_{89} = 6\frac{2}{3} + \frac{1}{3}(89 - 1)[/tex]
[tex]a_{89} = 6\frac{2}{3} + \frac{1}{3}(88)[/tex]
[tex]a_{89} = 6\frac{2}{3} + 29\frac{1}{3}[/tex]
[tex]a_{89} = 36[/tex]

The answer is B.

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