Answer :
Answer:[tex]\frac{1}{4}[/tex]
Explanation:
Given
Charge Q is spread over non conducting sheet
Electric field due to sheet is [tex]E=\frac{\sigma }{2\epsilon _o}[/tex]
where [tex]\sigma =\frac{charge}{area}=\frac{q}{d^2}[/tex]
[tex]E=\frac{q}{2d^2\epsilon _o}[/tex]
Now if the sheet is stretch to becomes [tex]2d[/tex] length
[tex]E'=\frac{q}{2(2d)^2\epsilon _o}[/tex]
[tex]E'=\frac{1}{4}\times E[/tex]
[tex]E'=\frac{E}{4}[/tex]
thus the ratio of new and initial electric field is [tex]\frac{1}{4}[/tex]