Answer :
Hello,
It is an immediate.
(Arccos ax)'=[tex] \dfrac{-a}{ \sqrt{1-(ax)^2} } [/tex] 0<Arccos (ax) <π
It is an immediate.
(Arccos ax)'=[tex] \dfrac{-a}{ \sqrt{1-(ax)^2} } [/tex] 0<Arccos (ax) <π