Answer :
Answer:
a) Fg = 9.495x10⁻⁶N
b) Fg = 3.908x10⁻⁶N
c)
[tex]F_{g} =\frac{Gm_{1}m_{2}R }{r^{3} }[/tex]
Explanation:
Given:
m₁ = mass = 3x10⁴kg
r = radius = 1 m
m₂ = 9.3 kg
Questions:
a) What is the magnitude of the gravitational force due to the sphere located at R = 1.4 m, Fg = ?
b) What is the magnitude of the gravitational force due to the sphere located at R= 0.21 m, Fg = ?
c) Write a general expression for the magnitude of the gravitational force on the particle at a distance r ≤ 1.0 m from the center of the sphere.
a) Since R > r, the equation for the gravitational force is:
[tex]F_{g} =\frac{Gm_{1}m_{2} }{R^{2} }[/tex]
Here,
G = gravitational constant = 6.67x10⁻¹¹m³/s² kg
Substituting values:
[tex]F_{g} =\frac{6.67x10^{-11}*3x10^{4}*9.3 }{1.4^{2} } =9.495x10^{-6} N[/tex]
b) Since R < r, the equation for the gravitational force is:
[tex]F_{g} =\frac{Gm_{1}m_{2}R }{r^{3} } =\frac{6.67x10^{-11}*3x10^{4}*9.3*0.21 }{1^{3} } =3.908x10^{-6} N[/tex]
c) The general expression for the magnitude of the gravitational force on the particle at a distance r ≤ 1.0 is the same to b)
[tex]F_{g} =\frac{Gm_{1}m_{2} R}{r^{3} }[/tex]