Answer :
Answer:
0.078 or 7.8%
Step-by-step explanation:
Mean salary (μ) = $37,764
Standard deviation (σ) = $5,100
The z-score for any given teacher's salary in California, X, is determined by:
[tex]z=\frac{X-\mu}{\sigma}[/tex]
For X = $45,000:
[tex]z=\frac{45,000-37,764}{5,100}\\ z=1.419[/tex]
A z-score of 1.419 corresponds to the 92.20th percentile of a normal distribution. Therefore, the probability that a salary is greater than $45,000 is:
[tex]P(X>\$45,000) = 1-0.9220\\P(X>\$45,000) = 0.078=7.8\%[/tex]
The probability is 0.078 or 7.8%.