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Suppose a normal distribution has a mean of 26 and a standard deviation of 4. What is the probability that a data value is between 27 and 28? Round your answer to the nearest tenth of a percent.

A. 12.3%
B. 9.3%
C. 10.3%
D. 11.3%

Answer :

Answer:

Answer is B. 9.3

Step-by-step explanation:

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There is a probability of 9.3% that the normal distribution data value is between 27 and 28

What is z score?

The z score is used to determine by how many standard deviations the raw score is above or below the mean. It is given by:

z = (raw score - mean)/standard deviation

Given that:

mean of 26 and a standard deviation of 4, For:

For x = 27:

z = (27 - 26) / 4 = 0.25

For x = 28:

z = (28 - 26) / 4 = 0.5

P(0.25 < z < 0.5) = P(z < 0.5) - P(z < 0.25) = 0.6915 - 0.5987 = 0.093

There is a probability of 9.3% that the normal distribution data value is between 27 and 28

Find out more on z score at: https://brainly.com/question/25638875

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