Answer :
Answer:
87.7 degrees.
Step-by-step explanation:
In triangle ABC, attached.
The height of the building |AB|=443 meters
The distance of the agent across the street , |BC|=18 meters
We want to determine the angle at C.
Now,
[tex]Tan C=\dfrac{|AB|}{|BC|} \\C=arctan (\dfrac{|AB|}{|BC|} )\\=arctan (\dfrac{443}{18} )\\=87.67^\circ\\\approx 87.7^\circ $(correct to the nearest tenth)[/tex]
The agent should sfoot his laser gun at an angle of 87.7 degrees.
