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Simply by living, an 87.5 kg human being will consume approximately 20.0 mol of O 2 per day. To provide energy for the human, the O 2 is reduced to H 2 O duing food oxidation by the reaction O 2 + 4 H + + 4 e − − ⇀ ↽ − 2 H 2 O Determine the current generated by the human per day. In this case, the current is defined as the flow of electrons ( e − ) to O 2 from the food the human consumes.

Answer :

ajeigbeibraheem

Answer:

The current generated by the human per day = 89.34 Amperes

Explanation:

Given that ;

the human consumes 20.0  mole of O₂ per day

The Food oxidation is given by the reaction :

[tex]O_2 + 4 H^+ + 4 e^- ----> 2H_2O[/tex]

So; the human will produce  20.0 × 4 moles of e⁻

Thus; moles of e⁻ produced  is = 80

Charge on 1  e⁻ = 1.602 × 10⁻¹⁹  C

e⁻ in 1 mole = 6.023 × 10²³

The total charge per day = [tex]\frac{1.602*10^{-19}*6.023*10^{23}*80}{24*60*60}[/tex]

= 89.34 Amperes

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