littrellke
Answered

A motorboat takes 5 hours to travel 200 kilometers going upstream. The return trip takes 4 hours going downstream. What is the rate of the boat in still water and what is the rate of the current?

Answer :

ananya37933

Answer:

Step-by-step explanation:

let x=rate of boat in still water

let c=rate of current

x+c=rate of boat downstream

x-c=rate of boat upstream

travel time *rate=distance

..

5(x-c)=200

4(x+c)=200

..

 

5x-5c=200

4x+4c=200

..

20x-20c=800

20x+20c=1000

add:

40x=1800

x=45

subtract:

40c=200

c=5

rate of boat in still water=45 km/hr

rate of current=5 km/hr

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kapoorprachi783

The answers are

  • rate of boat in still water = 45 km/hr
  • rate of current = 5 km/hr

How do find the rate of boat in still water and the rate of current?

Given,

let x = rate of boat in still water

let c = rate of current

x+c = rate of boat downstream

x-c=rate of boat upstream

travel time *rate=distance

5 (x-c) = 200

4 (x+c) = 200

5x-5c=200

4x+4c=200

20x-20c=800

20x+20c=1000

add:

40 x = 1800

x = 45

subtract:

40 c = 200

c = 5

Rate of boat in still water = 45 km/hr

Rate of current = 5 km/hr

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