10 teams enter a soccer tournament. In the first round teams paired in 5 pairs to play with each other. Assume that now in each match one of the teams is marked as "HOME" and the other "AWAY" and first 5 games need to run one after another. How many different pairings are possible to create?

Answer :

Answer:

45 different pairings are possible to create

Step-by-step explanation:

Since one team is marked as "HOME" and other as "AWAY", the order in which the teams are chosen is important to solve this question. So we use the permutations formula to solve.

Permutations formula:

The number of possible permutations of x elements from a set of n elements is given by the following formula:

[tex]P_{(n,x)} = \frac{n!}{(n-x)!}[/tex]

In this question:

Combinations of 2 teams from sets of 10. SO

[tex]P_{(10,2)} = \frac{10!}{(10-2)!} = 95[/tex]

45 different pairings are possible to create

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