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the singh and robinson families planned a trip to busch gardens. they needed to buy one ticket per person and then pay for parking. the singh's spent $335 for 5 people and the robinsons spent $ 465 for 7 people. how much did each ticket cost? How much was parking

Answer :

Let x represent cost of each ticket and y represent cost of parking.

We have been given that the Singh's spent $335 for 5 people and parking. We can represent this information in an equation as:

[tex]5x+y=335...(1)[/tex]

We are also told that the Robinson spent $465 for 7 people and parking. We can represent this information in an equation as:

[tex]7x+y=465...(2)[/tex]

Now we will use elimination method to solve our given system of equations.

Upon subtracting equation (1) from equation (2), we will get:

[tex]7x-5x+y-y=465-335[/tex]

[tex]2x=130[/tex]

[tex]\frac{2x}{2}=\frac{130}{2}[/tex]

[tex]x=65[/tex]

Therefore, the each ticket costs $65.

Upon substituting [tex]x=65[/tex] in equation (1), we will get:

[tex]5(65)+y=335[/tex]

[tex]325+y=335[/tex]

[tex]325-325+y=335-325[/tex]

[tex]y=10[/tex]

Therefore, the parking costs $10.

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